Problem Set: At the sixth-grade school dance, there are 132 boys, 89 girls, and 14 adults.a. Write the ratio of the number of boys to the number of girls.b. Write the same ratio using another form (A: B vs. A to B).c. Write the ratio of the number of boys to the number of adults.d. Write the same ratio using another form.*Answer A-D

Answer:Part a) [tex]\frac{132}{89}[/tex]Part b) 132:89 vs 132 to 89Part c) [tex]\frac{66}{7}[/tex]Part d) 66:7 vs 66 to 7Step-by-step explanation:Letx ----> the number of boysy ----> the number girlsz ----> the number of adultswe havex=132, y=89, z=14Part a) Write the ratio of the number of boys to the number of girls.To find the ratio of the number of boys to the number of girls, divide the number of boys by the number of girlsso[tex]\frac{x}{y}[/tex]substitute[tex]\frac{132}{89}[/tex]Part b) Write the same ratio using another form (A: B vs. A to B)we have[tex]\frac{132}{89}[/tex]The other form is132:89 vs 132 to 89Part c) Write the ratio of the number of boys to the number of adultsTo find the ratio of the number of boys to the number of adults, divide the number of boys by the number of adultsso[tex]\frac{x}{z}[/tex]substitute[tex]\frac{132}{14}[/tex]Simplify[tex]\frac{66}{7}[/tex]Part d) Write the same ratio using another formThe other form is66:7 vs 66 to 7